A-Best: Remember i = root(-1)
So, i^x, for any even x = -1
i^99 - i^3
= i^(98)*i^(1) - i^(2)*i^(1)
= i^1 - i^1
= -i + i
= 0
If i is not root(-1), i.e. you have not studied complex numbers yet and i is just a variable then...
i^99 - i^3
= i^3 (i^96 - 1)
is as far as you can get